What is the axis x^2+8x+12 ?

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axis x^2+8x+12

axis

x^{2} + 8 x + 12

x = - 4

Solution steps

y = x^{2} + 8 x + 12

Rewrite

y = x^{2} + 8 x + 12

in the standard form

4 \cdot \frac{1}{4} (y - (- 4)) = (x - (- 4))^{2}

Therefore parabola properties are:

(h, k) = (- 4, - 4), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 4

y = 2 (x + 3)^{2} + 4

f (x) = - 3 x^{2} + 5 x - 2

- x^{2} + 10 x - 24

y = \frac{x ^{2} - 16 x + 70}{2}

x = (2 y + 5) (y + 6)