What is the axis x=(2y+5)(y+6) ?

The axis x=(2y+5)(y+6) is y=-17/4

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axis x=(2y+5)(y+6)

axis

x = (2 y + 5) (y + 6)

y = - \frac{17}{4}

Solution steps

x = (2 y + 5) (y + 6)

Rewrite

x = (2 y + 5) (y + 6)

in the standard form

4 \cdot \frac{1}{8} (x - (- \frac{49}{8})) = (y - (- \frac{17}{4}))^{2}

Therefore parabola properties are:

(h, k) = (- \frac{49}{8}, - \frac{17}{4}), p = \frac{1}{8}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = - \frac{17}{4}

y = x^{2} + 12 x + 43

y = (0.5 - x)^{2}

y = - x^{2} - 3 x + 4

y = (x - 2 + 5) (x - 2 - 5)

x^{2} + 2 x + 3 y + 22 = 0