What is the axis y=x^2+10x ?

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axis y=x^2+10x

axis

y = x^{2} + 10 x

x = - 5

Solution steps

y = x^{2} + 10 x

Rewrite

y = x^{2} + 10 x

in the standard form

4 \cdot \frac{1}{4} (y - (- 25)) = (x - (- 5))^{2}

Therefore parabola properties are:

(h, k) = (- 5, - 25), p = \frac{1}{4}

Parabola is of the form

4 p (y - k) = (x - h)^{2}

and is symmetric around the

y

-axis

Axis of symmetry is a line parallel to the

y

-axis which intersects the vertex:

x = - 5

x = (- 20 y + 13)^{2}

(x - 3)^{2} = 12 (y - 1)

(x + 2)^{2} = - 8 y

y = 10 - 2 x^{2}

y = - 3 x^{2} + 10