What is the axis x=(-20y+13)^2 ?

The axis x=(-20y+13)^2 is y= 13/20

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axis x=(-20y+13)^2

axis

x = (- 20 y + 13)^{2}

y = \frac{13}{20}

Solution steps

x = (- 20 y + 13)^{2}

Rewrite

x = (- 20 y + 13)^{2}

in the standard form:

4 \cdot \frac{1}{1600} (x - 0) = (y - \frac{13}{20})^{2}

Therefore parabola properties are:

(h, k) = (0, \frac{13}{20}), p = \frac{1}{1600}

Parabola is of the form

4 p (x - h) = (y - k)^{2}

and is symmetric around the

x

-axis

Axis of symmetry is a line parallel to the

x

-axis which intersects the vertex:

y = \frac{13}{20}

(x - 3)^{2} = 12 (y - 1)

(x + 2)^{2} = - 8 y

y = 10 - 2 x^{2}

y = - 3 x^{2} + 10

y = 3 x^{2} - 10 x + 5