What is x^2+(y-1)^2=4 ?

The solution to x^2+(y-1)^2=4 is Circle with (a,b)=(0,1),r=2

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x^2+(y-1)^2=4

x^{2} + (y - 1)^{2} = 4

(a, b) = (0, 1), r = 2

Solution steps

x^{2} + (y - 1)^{2} = 4

Rewrite

x^{2} + (y - 1)^{2} = 4

in the form of the standard circle equation

(x - 0)^{2} + (y - 1)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (0, 1), r = 2

x^{2} + y^{2} + 8 x - 14 y + 1 = 0

x^{2} + y^{2} - 5 x + 4 y = 46

x^{2} + y^{2} - 2 x - 4 y - 5 = 0

x^{2} + y^{2} - 2 x - 15 = 0

x^{2} - 14 x + y^{2} + 8 y + 40 = 0

What is x^2+(y-1)^2=4 ?
The solution to x^2+(y-1)^2=4 is Circle with (a,b)=(0,1),r=2