What is x^2+y^2-2x-15=0 ?

The solution to x^2+y^2-2x-15=0 is Circle with (a,b)=(1,0),r=4

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x^2+y^2-2x-15=0

x^{2} + y^{2} - 2 x - 15 = 0

(a, b) = (1, 0), r = 4

Solution steps

x^{2} + y^{2} - 2 x - 15 = 0

Rewrite

x^{2} + y^{2} - 2 x - 15 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - 0)^{2} = 4^{2}

Therefore the circle properties are:

(a, b) = (1, 0), r = 4

x^{2} - 14 x + y^{2} + 8 y + 40 = 0

9 x^{2} + 9 y^{2} + 42 x + 84 y + 65 = 0

4 x^{2} + 4 y^{2} - 16 x - 24 y + 51 = 0

2 x^{2} + 2 y^{2} - 2 x + 6 y = 45

9 x^{2} + 9 y^{2} - 6 x + 24 y = 19

What is x^2+y^2-2x-15=0 ?
The solution to x^2+y^2-2x-15=0 is Circle with (a,b)=(1,0),r=4