What is the area (x^2)/(8[3,7]) ?

The area (x^2)/(8[3,7]) is Unbounded

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area (x^2)/(8[3,7])

area

\frac{x ^{2}}{8 [ 3 , 7 ]}

Unbounded

Solution steps

y = \frac{x ^{2}}{8 [ 3 , 7 ]}

Rewrite

y = \frac{x ^{2}}{8 [ 3 , 7 ]}

in the standard form:

4 \cdot \frac{1}{4 ( \frac{1}{\frac{1}{\frac{1}{8 [ 3 , 7 ]}}} )} y - - \frac{0}{\frac{1}{\frac{1}{8 [ 3 , 7 ]}}} = (x - 0)^{2}

Therefore parabola properties are:

(h, k) = 0, - \frac{0}{\frac{1}{\frac{1}{8 [ 3 , 7 ]}}}, p = \frac{1}{4 ( \frac{1}{\frac{1}{\frac{1}{8 [ 3 , 7 ]}}} )}

Parabola's area is always unbounded

Unbounded

f (x) = - x^{2} + 3 x + 5

f (x) = - x^{2} + 3 x + 2

\frac{( y - 3 ) ^{2}}{5}

(- x + 2) - (x^{2} - 1)

x^{2} + 9 [- 1, 3]