What is 16x^2+16y^2=320 ?

The solution to 16x^2+16y^2=320 is Circle with (a,b)=(0,0),r=2sqrt(5)

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16x^2+16y^2=320

16 x^{2} + 16 y^{2} = 320

(a, b) = (0, 0), r = 25

Solution steps

16 x^{2} + 16 y^{2} = 320

Rewrite

16 x^{2} + 16 y^{2} = 320

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (25)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 25

(x - 2)^{2} + (y + 1)^{2} = 9

(x - 3)^{2} + (y + 1)^{2} = 16

4 x^{2} - 4 x + 4 y^{2} - 63 = 0

x^{2} + y^{2} - 9 x + 5 y - 10 = 0

x^{2} + y^{2} - 2 x - 4 y - 4 = 0

What is 16x^2+16y^2=320 ?
The solution to 16x^2+16y^2=320 is Circle with (a,b)=(0,0),r=2sqrt(5)