What is (x-6)^2+(y+1)^2=49 ?

The solution to (x-6)^2+(y+1)^2=49 is Circle with (a,b)=(6,-1),r=7

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(x-6)^2+(y+1)^2=49

(x - 6)^{2} + (y + 1)^{2} = 49

(a, b) = (6, - 1), r = 7

Solution steps

(x - 6)^{2} + (y + 1)^{2} = 49

Rewrite

(x - 6)^{2} + (y + 1)^{2} = 49

in the form of the standard circle equation

(x - 6)^{2} + (y - (- 1))^{2} = 7^{2}

Therefore the circle properties are:

(a, b) = (6, - 1), r = 7

x^{2} + 6 x + y^{2} - 2 y + 6 = 0

(x + 2)^{2} + (y + 5)^{2} = 7

4 x^{2} + 4 y^{2} - 4 x + 24 y + 1 = 0

(x - 4)^{2} + (y - 7)^{2} = 49

9 x^{2} + 9 y^{2} - 42 x + 84 y + 65 = 0

What is (x-6)^2+(y+1)^2=49 ?
The solution to (x-6)^2+(y+1)^2=49 is Circle with (a,b)=(6,-1),r=7