What is x^2+y^2+2x-y-1=0 ?

The solution to x^2+y^2+2x-y-1=0 is Circle with (a,b)=(-1, 1/2),r= 3/2

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x^2+y^2+2x-y-1=0

x^{2} + y^{2} + 2 x - y - 1 = 0

(a, b) = (- 1, \frac{1}{2}), r = \frac{3}{2}

Solution steps

x^{2} + y^{2} + 2 x - y - 1 = 0

Rewrite

x^{2} + y^{2} + 2 x - y - 1 = 0

in the form of the standard circle equation

(x - (- 1))^{2} + (y - \frac{1}{2})^{2} = (\frac{3}{2})^{2}

Therefore the circle properties are:

(a, b) = (- 1, \frac{1}{2}), r = \frac{3}{2}

y^{2} + x^{2} + 17 - 8 x + 4 y = 0

(x - 4)^{2} + (y - 4)^{2} = 27

x^{2} + y^{2} + 6 x + 10 y + 33 = 0

x^{2} + y^{2} - 5 x + 3 y - 2 = 0

(x + 11)^{2} + (y + 1)^{2} = 144

What is x^2+y^2+2x-y-1=0 ?
The solution to x^2+y^2+2x-y-1=0 is Circle with (a,b)=(-1, 1/2),r= 3/2