What is x^2+y^2-10x+12y+25=0 ?

The solution to x^2+y^2-10x+12y+25=0 is Circle with (a,b)=(5,-6),r=6

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x^2+y^2-10x+12y+25=0

x^{2} + y^{2} - 10 x + 12 y + 25 = 0

(a, b) = (5, - 6), r = 6

Solution steps

x^{2} + y^{2} - 10 x + 12 y + 25 = 0

Rewrite

x^{2} + y^{2} - 10 x + 12 y + 25 = 0

in the form of the standard circle equation

(x - 5)^{2} + (y - (- 6))^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (5, - 6), r = 6

(x + 4)^{2} + (y - 3)^{2} = 9

x^{2} + y^{2} - 16 x - 8 y = 0

(\frac{x - 7}{4})^{2} + (\frac{y + 3}{4})^{2} = \frac{169}{16}

x^{2} + y^{2} + 3 x + 4 y + 4 = 0

x^{2} + y^{2} - 10 x - 12 y + 45 = 0

What is x^2+y^2-10x+12y+25=0 ?
The solution to x^2+y^2-10x+12y+25=0 is Circle with (a,b)=(5,-6),r=6