What is (x+1)^2+(y+3)^2=5 ?

The solution to (x+1)^2+(y+3)^2=5 is Circle with (a,b)=(-1,-3),r=sqrt(5)

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(x+1)^2+(y+3)^2=5

(x + 1)^{2} + (y + 3)^{2} = 5

(a, b) = (- 1, - 3), r = 5

Solution steps

(x + 1)^{2} + (y + 3)^{2} = 5

Rewrite

(x + 1)^{2} + (y + 3)^{2} = 5

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 3))^{2} = (5)^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 3), r = 5

(x - 2)^{2} + (y + 5)^{2} = 16

x^{2} + (y + 5)^{2} = 25

(x - 3)^{2} + y^{2} = \frac{1}{9}

(x + 2)^{2} + y^{2} = 36

x^{2} + (y - 3960)^{2} = 396 0^{2}

What is (x+1)^2+(y+3)^2=5 ?
The solution to (x+1)^2+(y+3)^2=5 is Circle with (a,b)=(-1,-3),r=sqrt(5)