What is x^2+y^2-2x+10y-55=0 ?

The solution to x^2+y^2-2x+10y-55=0 is Circle with (a,b)=(1,-5),r=9

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x^2+y^2-2x+10y-55=0

x^{2} + y^{2} - 2 x + 10 y - 55 = 0

(a, b) = (1, - 5), r = 9

Solution steps

x^{2} + y^{2} - 2 x + 10 y - 55 = 0

Rewrite

x^{2} + y^{2} - 2 x + 10 y - 55 = 0

in the form of the standard circle equation

(x - 1)^{2} + (y - (- 5))^{2} = 9^{2}

Therefore the circle properties are:

(a, b) = (1, - 5), r = 9

x^{2} + y^{2} - 2 x + 4 y - 20 = 0

x^{2} + (y + 7)^{2} = 9

x^{2} - 6 x + 8 y + y^{2} = 0

x^{2} + 20 x + y^{2} - 14 y + 145 = 0

x^{2} + y^{2} - 4 x - 8 y + 11 = 0

What is x^2+y^2-2x+10y-55=0 ?
The solution to x^2+y^2-2x+10y-55=0 is Circle with (a,b)=(1,-5),r=9