What is x^2+20x+y^2-14y+145=0 ?

The solution to x^2+20x+y^2-14y+145=0 is Circle with (a,b)=(-10,7),r=2

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x^2+20x+y^2-14y+145=0

x^{2} + 20 x + y^{2} - 14 y + 145 = 0

(a, b) = (- 10, 7), r = 2

Solution steps

x^{2} + 20 x + y^{2} - 14 y + 145 = 0

Rewrite

x^{2} + 20 x + y^{2} - 14 y + 145 = 0

in the form of the standard circle equation

(x - (- 10))^{2} + (y - 7)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (- 10, 7), r = 2

x^{2} + y^{2} - 4 x - 8 y + 11 = 0

(x + 3)^{2} + (y - 4)^{2} = 16

(x - 3)^{(2)} + (y + 2)^{(2)} = 49

(x - \frac{3}{2})^{2} + (y - \frac{3}{2})^{2} = \frac{9}{4}

x^{2} - 6 x + y^{2} - 8 y = 39

What is x^2+20x+y^2-14y+145=0 ?
The solution to x^2+20x+y^2-14y+145=0 is Circle with (a,b)=(-10,7),r=2