What is x^2+y^2+20x-69=0 ?

The solution to x^2+y^2+20x-69=0 is Circle with (a,b)=(-10,0),r=13

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x^2+y^2+20x-69=0

x^{2} + y^{2} + 20 x - 69 = 0

(a, b) = (- 10, 0), r = 13

Solution steps

x^{2} + y^{2} + 20 x - 69 = 0

Rewrite

x^{2} + y^{2} + 20 x - 69 = 0

in the form of the standard circle equation

(x - (- 10))^{2} + (y - 0)^{2} = 1 3^{2}

Therefore the circle properties are:

(a, b) = (- 10, 0), r = 13

x^{2} + y^{2} - 2 x + 2 y + 1 = 0

2 x^{2} + 2 y^{2} - 3 x + 4 y - 1 = 0

x^{2} + y^{2} - 6 x - 8 y - 45 = 0

(x - 2)^{2} + (y - 1)^{2} = 1

2 x^{2} + 2 y^{2} - 50 = 0

What is x^2+y^2+20x-69=0 ?
The solution to x^2+y^2+20x-69=0 is Circle with (a,b)=(-10,0),r=13