What is 2x^2+2y^2-50=0 ?

The solution to 2x^2+2y^2-50=0 is Circle with (a,b)=(0,0),r=5

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2x^2+2y^2-50=0

2 x^{2} + 2 y^{2} - 50 = 0

(a, b) = (0, 0), r = 5

Solution steps

2 x^{2} + 2 y^{2} - 50 = 0

Rewrite

2 x^{2} + 2 y^{2} - 50 = 0

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 5

3 x^{2} + 3 y^{2} + 6 x - 3 y - 2 = 0

y^{2} = - x^{2} + 25

(x + 4)^{2} + y^{2} = 25

a^{2} + b^{2} = 2

x^{2} + y^{2} - 10 x - 4 y + 20 = 0

What is 2x^2+2y^2-50=0 ?
The solution to 2x^2+2y^2-50=0 is Circle with (a,b)=(0,0),r=5