What is (x+4)^2+y^2=25 ?

The solution to (x+4)^2+y^2=25 is Circle with (a,b)=(-4,0),r=5

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(x+4)^2+y^2=25

(x + 4)^{2} + y^{2} = 25

(a, b) = (- 4, 0), r = 5

Solution steps

(x + 4)^{2} + y^{2} = 25

Rewrite

(x + 4)^{2} + y^{2} = 25

in the form of the standard circle equation

(x - (- 4))^{2} + (y - 0)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 4, 0), r = 5

a^{2} + b^{2} = 2

x^{2} + y^{2} - 10 x - 4 y + 20 = 0

(x + 6)^{2} + (y - 7)^{2} = 36

2 x^{2} + 2 y^{2} = 50

x^{2} + y^{2} - 12 x + 4 y - 140 = 0

What is (x+4)^2+y^2=25 ?
The solution to (x+4)^2+y^2=25 is Circle with (a,b)=(-4,0),r=5