What is x^2+y^2-10x-4y+20=0 ?

The solution to x^2+y^2-10x-4y+20=0 is Circle with (a,b)=(5,2),r=3

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x^2+y^2-10x-4y+20=0

x^{2} + y^{2} - 10 x - 4 y + 20 = 0

(a, b) = (5, 2), r = 3

Solution steps

x^{2} + y^{2} - 10 x - 4 y + 20 = 0

Rewrite

x^{2} + y^{2} - 10 x - 4 y + 20 = 0

in the form of the standard circle equation

(x - 5)^{2} + (y - 2)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (5, 2), r = 3

(x + 6)^{2} + (y - 7)^{2} = 36

2 x^{2} + 2 y^{2} = 50

x^{2} + y^{2} - 12 x + 4 y - 140 = 0

x^{2} + y^{2} + 2 x + 2 y = 7

x^{2} - 10 x + y^{2} + 8 = 0

What is x^2+y^2-10x-4y+20=0 ?
The solution to x^2+y^2-10x-4y+20=0 is Circle with (a,b)=(5,2),r=3