What is x^2+y^2+2x+2y=7 ?

The solution to x^2+y^2+2x+2y=7 is Circle with (a,b)=(-1,-1),r=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2+2x+2y=7

x^{2} + y^{2} + 2 x + 2 y = 7

(a, b) = (- 1, - 1), r = 3

Solution steps

x^{2} + y^{2} + 2 x + 2 y = 7

Rewrite

x^{2} + y^{2} + 2 x + 2 y = 7

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 1))^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 1), r = 3

x^{2} - 10 x + y^{2} + 8 = 0

x^{2} + y^{2} - 4 x + 18 y + 35 = 0

- 4 y^{2} - 4 x^{2} - 20 x + 32 y + 81 = 0

4 (x - 3)^{2} + 4 y^{2} = 4

x^{2} + y^{2} + 2 x - 14 y = - 25

What is x^2+y^2+2x+2y=7 ?
The solution to x^2+y^2+2x+2y=7 is Circle with (a,b)=(-1,-1),r=3