What is x^2+y^2-18x-14y+66=0 ?

The solution to x^2+y^2-18x-14y+66=0 is Circle with (a,b)=(9,7),r=8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^2+y^2-18x-14y+66=0

x^{2} + y^{2} - 18 x - 14 y + 66 = 0

(a, b) = (9, 7), r = 8

Solution steps

x^{2} + y^{2} - 18 x - 14 y + 66 = 0

Rewrite

x^{2} + y^{2} - 18 x - 14 y + 66 = 0

in the form of the standard circle equation

(x - 9)^{2} + (y - 7)^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (9, 7), r = 8

x^{2} + y^{2} - 4 x + 8 y + 11 = 0

x^{2} + y^{2} + 10 x - 6 y - 2 = 0

x^{2} - 4 x + y^{2} + 6 y - 24 = 0

(x - 2)^{2} + y^{2} = 36

x^{2} + y^{2} - 8 x - 10 y = - 16

What is x^2+y^2-18x-14y+66=0 ?
The solution to x^2+y^2-18x-14y+66=0 is Circle with (a,b)=(9,7),r=8