What is x^2-4x+y^2+6y-24=0 ?

The solution to x^2-4x+y^2+6y-24=0 is Circle with (a,b)=(2,-3),r=sqrt(37)

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x^2-4x+y^2+6y-24=0

x^{2} - 4 x + y^{2} + 6 y - 24 = 0

(a, b) = (2, - 3), r = 37

Solution steps

x^{2} - 4 x + y^{2} + 6 y - 24 = 0

Rewrite

x^{2} - 4 x + y^{2} + 6 y - 24 = 0

in the form of the standard circle equation

(x - 2)^{2} + (y - (- 3))^{2} = (37)^{2}

Therefore the circle properties are:

(a, b) = (2, - 3), r = 37

(x - 2)^{2} + y^{2} = 36

x^{2} + y^{2} - 8 x - 10 y = - 16

4 x^{2} + 4 y^{2} - 12 x + 4 y - 26 = 0

x^{2} + y^{2} - 18 x - 6 y - 10 = 0

3 x^{2} + 3 y^{2} + 30 x - 48 y + 123 = 0

What is x^2-4x+y^2+6y-24=0 ?
The solution to x^2-4x+y^2+6y-24=0 is Circle with (a,b)=(2,-3),r=sqrt(37)