What is 3x^2+3y^2+30x-48y+123=0 ?

The solution to 3x^2+3y^2+30x-48y+123=0 is Circle with (a,b)=(-5,8),r=4sqrt(3)

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3x^2+3y^2+30x-48y+123=0

3 x^{2} + 3 y^{2} + 30 x - 48 y + 123 = 0

(a, b) = (- 5, 8), r = 43

Solution steps

3 x^{2} + 3 y^{2} + 30 x - 48 y + 123 = 0

Rewrite

3 x^{2} + 3 y^{2} + 30 x - 48 y + 123 = 0

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 8)^{2} = (43)^{2}

Therefore the circle properties are:

(a, b) = (- 5, 8), r = 43

(x + 3)^{2} + y^{2} = 25

(x + 3)^{2} + y^{2} = 81

x^{2} + y^{2} - 1 \geq 0

x^{2} = 1 - y^{2}

(y + 8)^{2} + (x + 2)^{2} = 72

What is 3x^2+3y^2+30x-48y+123=0 ?
The solution to 3x^2+3y^2+30x-48y+123=0 is Circle with (a,b)=(-5,8),r=4sqrt(3)