What is (x+3)^2+y^2=81 ?

The solution to (x+3)^2+y^2=81 is Circle with (a,b)=(-3,0),r=9

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x+3)^2+y^2=81

(x + 3)^{2} + y^{2} = 81

(a, b) = (- 3, 0), r = 9

Solution steps

(x + 3)^{2} + y^{2} = 81

Rewrite

(x + 3)^{2} + y^{2} = 81

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 0)^{2} = 9^{2}

Therefore the circle properties are:

(a, b) = (- 3, 0), r = 9

x^{2} + y^{2} - 1 \geq 0

x^{2} = 1 - y^{2}

(y + 8)^{2} + (x + 2)^{2} = 72

x^{2} + y^{2} = 9 x

x^{2} + y^{2} - 2 x + 2 y - 2 = 0

What is (x+3)^2+y^2=81 ?
The solution to (x+3)^2+y^2=81 is Circle with (a,b)=(-3,0),r=9