What is (x-2)^2+(y-4)^2=100 ?

The solution to (x-2)^2+(y-4)^2=100 is Circle with (a,b)=(2,4),r=10

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(x-2)^2+(y-4)^2=100

(x - 2)^{2} + (y - 4)^{2} = 100

(a, b) = (2, 4), r = 10

Solution steps

(x - 2)^{2} + (y - 4)^{2} = 100

Rewrite

(x - 2)^{2} + (y - 4)^{2} = 100

in the form of the standard circle equation

(x - 2)^{2} + (y - 4)^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (2, 4), r = 10

x^{2} - 6 x + y^{2} - 7 = 0

x^{2} + y^{2} - 9 x + 4 y - 127 = 0

(x - 5)^{2} + (y - 4)^{2} = 36

(x - (- 5))^{2} + (y - (- 6))^{2} = \frac{2}{3}

x^{2} + y^{2} - 6 x - 18 y + 41 = 0

What is (x-2)^2+(y-4)^2=100 ?
The solution to (x-2)^2+(y-4)^2=100 is Circle with (a,b)=(2,4),r=10