What is (x-5)^2+(y-4)^2=36 ?

The solution to (x-5)^2+(y-4)^2=36 is Circle with (a,b)=(5,4),r=6

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(x-5)^2+(y-4)^2=36

(x - 5)^{2} + (y - 4)^{2} = 36

(a, b) = (5, 4), r = 6

Solution steps

(x - 5)^{2} + (y - 4)^{2} = 36

Rewrite

(x - 5)^{2} + (y - 4)^{2} = 36

in the form of the standard circle equation

(x - 5)^{2} + (y - 4)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (5, 4), r = 6

(x - (- 5))^{2} + (y - (- 6))^{2} = \frac{2}{3}

x^{2} + y^{2} - 6 x - 18 y + 41 = 0

(x - 1)^{2} + (y - 2)^{2} = 3^{2}

x^{2} + (y + \frac{3}{5})^{2} = 27

x^{2} + y^{2} - 8 x + 12 y + 45 = 0

What is (x-5)^2+(y-4)^2=36 ?
The solution to (x-5)^2+(y-4)^2=36 is Circle with (a,b)=(5,4),r=6