What is 5x^2+5y^2-2x-30y+42=0 ?

The solution to 5x^2+5y^2-2x-30y+42=0 is Circle with (a,b)=(1/5 ,3),r= 4/5

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5x^2+5y^2-2x-30y+42=0

5 x^{2} + 5 y^{2} - 2 x - 30 y + 42 = 0

(a, b) = (\frac{1}{5}, 3), r = \frac{4}{5}

Solution steps

5 x^{2} + 5 y^{2} - 2 x - 30 y + 42 = 0

Rewrite

5 x^{2} + 5 y^{2} - 2 x - 30 y + 42 = 0

in the form of the standard circle equation

(x - \frac{1}{5})^{2} + (y - 3)^{2} = (\frac{4}{5})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{5}, 3), r = \frac{4}{5}

2 x^{2} + 2 y^{2} + 6 x - 8 y = - 12

x^{2} + y^{2} = - 2 x

(x - 3)^{2} + (y - 2)^{2} = 3

x^{2} + y^{2} + 3 x - 6 y + 9 = 0

x^{2} + y^{2} + 6 x + 18 y + 9 = 0

What is 5x^2+5y^2-2x-30y+42=0 ?
The solution to 5x^2+5y^2-2x-30y+42=0 is Circle with (a,b)=(1/5 ,3),r= 4/5