What is (x-3)^2+(y-2)^2=3 ?

The solution to (x-3)^2+(y-2)^2=3 is Circle with (a,b)=(3,2),r=sqrt(3)

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(x-3)^2+(y-2)^2=3

(x - 3)^{2} + (y - 2)^{2} = 3

(a, b) = (3, 2), r = 3

Solution steps

(x - 3)^{2} + (y - 2)^{2} = 3

Rewrite

(x - 3)^{2} + (y - 2)^{2} = 3

in the form of the standard circle equation

(x - 3)^{2} + (y - 2)^{2} = (3)^{2}

Therefore the circle properties are:

(a, b) = (3, 2), r = 3

x^{2} + y^{2} + 3 x - 6 y + 9 = 0

x^{2} + y^{2} + 6 x + 18 y + 9 = 0

x^{2} + y^{2} + 8 x + 7 = 0

(x + 4)^{2} + (y - 1)^{2} = 25

x^{2} + y^{2} + 14 x + 12 y + 21 = 0

What is (x-3)^2+(y-2)^2=3 ?
The solution to (x-3)^2+(y-2)^2=3 is Circle with (a,b)=(3,2),r=sqrt(3)