What is x^2+y^2+14x+12y+21=0 ?

The solution to x^2+y^2+14x+12y+21=0 is Circle with (a,b)=(-7,-6),r=8

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x^2+y^2+14x+12y+21=0

x^{2} + y^{2} + 14 x + 12 y + 21 = 0

(a, b) = (- 7, - 6), r = 8

Solution steps

x^{2} + y^{2} + 14 x + 12 y + 21 = 0

Rewrite

x^{2} + y^{2} + 14 x + 12 y + 21 = 0

in the form of the standard circle equation

(x - (- 7))^{2} + (y - (- 6))^{2} = 8^{2}

Therefore the circle properties are:

(a, b) = (- 7, - 6), r = 8

4 x^{2} + 32 x + 4 y^{2} = 0

4 x^{2} + 4 y^{2} - 16 x + 40 y - 7 = 0

(x - 11)^{2} + (y - 12)^{2} = 25

y^{2} + x^{2} - 4 = 0

x^{2} + y^{2} - 6 x - 10 y + 2 = 0

What is x^2+y^2+14x+12y+21=0 ?
The solution to x^2+y^2+14x+12y+21=0 is Circle with (a,b)=(-7,-6),r=8