What is (x-11)^2+(y-12)^2=25 ?

The solution to (x-11)^2+(y-12)^2=25 is Circle with (a,b)=(11,12),r=5

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(x-11)^2+(y-12)^2=25

(x - 11)^{2} + (y - 12)^{2} = 25

(a, b) = (11, 12), r = 5

Solution steps

(x - 11)^{2} + (y - 12)^{2} = 25

Rewrite

(x - 11)^{2} + (y - 12)^{2} = 25

in the form of the standard circle equation

(x - 11)^{2} + (y - 12)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (11, 12), r = 5

y^{2} + x^{2} - 4 = 0

x^{2} + y^{2} - 6 x - 10 y + 2 = 0

(x - 5)^{2} + (y - 1)^{2} = 4

x^{2} + y^{2} - 8 x + 2 y - 24 = 0

x^{2} + y^{2} - 4 x - 2 y - 31 = 0

What is (x-11)^2+(y-12)^2=25 ?
The solution to (x-11)^2+(y-12)^2=25 is Circle with (a,b)=(11,12),r=5