What is x^2+y^2-8x+2y-24=0 ?

The solution to x^2+y^2-8x+2y-24=0 is Circle with (a,b)=(4,-1),r=sqrt(41)

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x^2+y^2-8x+2y-24=0

x^{2} + y^{2} - 8 x + 2 y - 24 = 0

(a, b) = (4, - 1), r = 41

Solution steps

x^{2} + y^{2} - 8 x + 2 y - 24 = 0

Rewrite

x^{2} + y^{2} - 8 x + 2 y - 24 = 0

in the form of the standard circle equation

(x - 4)^{2} + (y - (- 1))^{2} = (41)^{2}

Therefore the circle properties are:

(a, b) = (4, - 1), r = 41

x^{2} + y^{2} - 4 x - 2 y - 31 = 0

(x + 2)^{2} + (y - 1)^{2} = 3

(x + 4)^{2} + (y - 34)^{2} = 1

2 (x - 2)^{2} + 2 y^{2} = 2

x^{2} + y^{2} - 6 x - 2 y - 15 = 0

What is x^2+y^2-8x+2y-24=0 ?
The solution to x^2+y^2-8x+2y-24=0 is Circle with (a,b)=(4,-1),r=sqrt(41)