What is (x+2)^2+(y-1)^2=3 ?

The solution to (x+2)^2+(y-1)^2=3 is Circle with (a,b)=(-2,1),r=sqrt(3)

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(x+2)^2+(y-1)^2=3

(x + 2)^{2} + (y - 1)^{2} = 3

(a, b) = (- 2, 1), r = 3

Solution steps

(x + 2)^{2} + (y - 1)^{2} = 3

Rewrite

(x + 2)^{2} + (y - 1)^{2} = 3

in the form of the standard circle equation

(x - (- 2))^{2} + (y - 1)^{2} = (3)^{2}

Therefore the circle properties are:

(a, b) = (- 2, 1), r = 3

(x + 4)^{2} + (y - 34)^{2} = 1

2 (x - 2)^{2} + 2 y^{2} = 2

x^{2} + y^{2} - 6 x - 2 y - 15 = 0

x^{2} + y^{2} - \frac{23}{2} x + \frac{11}{2} - \frac{13}{2} = 0

(x + 5)^{2} + (y - 8)^{2} = 25

What is (x+2)^2+(y-1)^2=3 ?
The solution to (x+2)^2+(y-1)^2=3 is Circle with (a,b)=(-2,1),r=sqrt(3)