What is ((y-2)^2)/9+((x-1/2)^2)/9 =1 ?

The solution to ((y-2)^2)/9+((x-1/2)^2)/9 =1 is Circle with (a,b)=(1/2 ,2),r=3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

((y-2)^2)/9+((x-1/2)^2)/9 =1

\frac{( y - 2 ) ^{2}}{9} + \frac{( x - \frac{1}{2} ) ^{2}}{9} = 1

(a, b) = (\frac{1}{2}, 2), r = 3

Solution steps

\frac{( y - 2 ) ^{2}}{9} + \frac{( x - \frac{1}{2} ) ^{2}}{9} = 1

Rewrite

\frac{( y - 2 ) ^{2}}{9} + \frac{( x - \frac{1}{2} ) ^{2}}{9} = 1

in the form of the standard circle equation

(x - \frac{1}{2})^{2} + (y - 2)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{2}, 2), r = 3

x^{2} + y^{2} - 4 x + 10 y - 7 = 0

(x + 1)^{2} + (y + 1)^{2} = 100

x^{2} + y^{2} = 250

x^{2} + y^{2} - 31 = 2 x + 4

x^{2} + y^{2} + 4 x - 14 y + 46 = 0

What is ((y-2)^2)/9+((x-1/2)^2)/9 =1 ?
The solution to ((y-2)^2)/9+((x-1/2)^2)/9 =1 is Circle with (a,b)=(1/2 ,2),r=3