What is (x+1)^2+(y+1)^2=100 ?

The solution to (x+1)^2+(y+1)^2=100 is Circle with (a,b)=(-1,-1),r=10

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(x+1)^2+(y+1)^2=100

(x + 1)^{2} + (y + 1)^{2} = 100

(a, b) = (- 1, - 1), r = 10

Solution steps

(x + 1)^{2} + (y + 1)^{2} = 100

Rewrite

(x + 1)^{2} + (y + 1)^{2} = 100

in the form of the standard circle equation

(x - (- 1))^{2} + (y - (- 1))^{2} = 1 0^{2}

Therefore the circle properties are:

(a, b) = (- 1, - 1), r = 10

x^{2} + y^{2} = 250

x^{2} + y^{2} - 31 = 2 x + 4

x^{2} + y^{2} + 4 x - 14 y + 46 = 0

3 x^{2} + 3 y^{2} - 6 x + 9 y + 5 = 0

2 x^{2} + 12 x + 18 - y^{2} = 3 (2 - y^{2}) + 4 y

What is (x+1)^2+(y+1)^2=100 ?
The solution to (x+1)^2+(y+1)^2=100 is Circle with (a,b)=(-1,-1),r=10