What is 3(x-3)^2+3y^2=12 ?

The solution to 3(x-3)^2+3y^2=12 is Circle with (a,b)=(3,0),r=2

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3(x-3)^2+3y^2=12

3 (x - 3)^{2} + 3 y^{2} = 12

(a, b) = (3, 0), r = 2

Solution steps

3 (x - 3)^{2} + 3 y^{2} = 12

Rewrite

3 (x - 3)^{2} + 3 y^{2} = 12

in the form of the standard circle equation

(x - 3)^{2} + (y - 0)^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (3, 0), r = 2

x^{2} + y^{2} - 10 y + 16 = 0

x^{2} + y^{2} + 2 x - 2 y = 0

9 x^{2} + 54 x + 9 y^{2} - 6 y + 64 = 0

x^{2} + y^{2} - 6 x + 8 y + 9 = 0

x^{2} + y^{2} + 12 x + 10 y + 41 = 0

What is 3(x-3)^2+3y^2=12 ?
The solution to 3(x-3)^2+3y^2=12 is Circle with (a,b)=(3,0),r=2