What is 9x^2+54x+9y^2-6y+64=0 ?

The solution to 9x^2+54x+9y^2-6y+64=0 is Circle with (a,b)=(-3, 1/3),r=sqrt(2)

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9x^2+54x+9y^2-6y+64=0

9 x^{2} + 54 x + 9 y^{2} - 6 y + 64 = 0

(a, b) = (- 3, \frac{1}{3}), r = 2

Solution steps

9 x^{2} + 54 x + 9 y^{2} - 6 y + 64 = 0

Rewrite

9 x^{2} + 54 x + 9 y^{2} - 6 y + 64 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - \frac{1}{3})^{2} = (2)^{2}

Therefore the circle properties are:

(a, b) = (- 3, \frac{1}{3}), r = 2

x^{2} + y^{2} - 6 x + 8 y + 9 = 0

x^{2} + y^{2} + 12 x + 10 y + 41 = 0

(x - 4)^{2} + (y + 1)^{2} = 5

(x + 3)^{2} + (y - 7)^{2} = 9

(x - 3)^{2} + 2 y + 1 - 81 = - y^{2}

What is 9x^2+54x+9y^2-6y+64=0 ?
The solution to 9x^2+54x+9y^2-6y+64=0 is Circle with (a,b)=(-3, 1/3),r=sqrt(2)