What is x^2+y^2+3x+6y+9=0 ?

The solution to x^2+y^2+3x+6y+9=0 is Circle with (a,b)=(-3/2 ,-3),r= 3/2

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x^2+y^2+3x+6y+9=0

x^{2} + y^{2} + 3 x + 6 y + 9 = 0

(a, b) = (- \frac{3}{2}, - 3), r = \frac{3}{2}

Solution steps

x^{2} + y^{2} + 3 x + 6 y + 9 = 0

Rewrite

x^{2} + y^{2} + 3 x + 6 y + 9 = 0

in the form of the standard circle equation

(x - (- \frac{3}{2}))^{2} + (y - (- 3))^{2} = (\frac{3}{2})^{2}

Therefore the circle properties are:

(a, b) = (- \frac{3}{2}, - 3), r = \frac{3}{2}

(x - 2)^{2} + (y - 3)^{2} = 10

9 x^{2} + 9 y^{2} = 64

(x - 2)^{2} + (y - 3)^{2} = 49

4 x^{2} + 4 y^{2} + 16 x - 12 y + 1 = 0

x^{2} + y^{2} + 84 x - 22 y + 861 = 0

What is x^2+y^2+3x+6y+9=0 ?
The solution to x^2+y^2+3x+6y+9=0 is Circle with (a,b)=(-3/2 ,-3),r= 3/2