What is 3(x-5)^2+3y^2=27 ?

The solution to 3(x-5)^2+3y^2=27 is Circle with (a,b)=(5,0),r=3

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3(x-5)^2+3y^2=27

3 (x - 5)^{2} + 3 y^{2} = 27

(a, b) = (5, 0), r = 3

Solution steps

3 (x - 5)^{2} + 3 y^{2} = 27

Rewrite

3 (x - 5)^{2} + 3 y^{2} = 27

in the form of the standard circle equation

(x - 5)^{2} + (y - 0)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (5, 0), r = 3

(x - 4)^{2} + y^{2} = 9

(x - 4)^{2} + y^{2} = 1

(x + 2)^{2} + (y + 5)^{2} = 100

x^{2} + y^{2} - 16 x + 8 y + 71 = 0

x^{2} - 2 x + y^{2} = 0

What is 3(x-5)^2+3y^2=27 ?
The solution to 3(x-5)^2+3y^2=27 is Circle with (a,b)=(5,0),r=3