What is (x-3)^2+y^2=36 ?

The solution to (x-3)^2+y^2=36 is Circle with (a,b)=(3,0),r=6

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(x-3)^2+y^2=36

(x - 3)^{2} + y^{2} = 36

(a, b) = (3, 0), r = 6

Solution steps

(x - 3)^{2} + y^{2} = 36

Rewrite

(x - 3)^{2} + y^{2} = 36

in the form of the standard circle equation

(x - 3)^{2} + (y - 0)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (3, 0), r = 6

(x - 4)^{2} + (y + 1)^{2} = 49

(x + 1)^{2} + (y + 2)^{2} = 16

x^{2} - 2 x + y^{2} + 8 y - 8 = 0

(x - 1)^{2} + y^{2} = 3

(x - 1)^{2} + y^{2} = 5

What is (x-3)^2+y^2=36 ?
The solution to (x-3)^2+y^2=36 is Circle with (a,b)=(3,0),r=6