What is (x-1)^2+y^2=5 ?

The solution to (x-1)^2+y^2=5 is Circle with (a,b)=(1,0),r=sqrt(5)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(x-1)^2+y^2=5

(x - 1)^{2} + y^{2} = 5

(a, b) = (1, 0), r = 5

Solution steps

(x - 1)^{2} + y^{2} = 5

Rewrite

(x - 1)^{2} + y^{2} = 5

in the form of the standard circle equation

(x - 1)^{2} + (y - 0)^{2} = (5)^{2}

Therefore the circle properties are:

(a, b) = (1, 0), r = 5

(x + 1)^{2} + (y + 3)^{2} = 11

x^{2} + y^{2} + 10 y + 11 = 0

x^{2} + y^{2} + 10 x - 8 y - 6 = 0

2 x^{2} + 2 y^{2} - 4 x + 12 y - 12 = 0

x^{2} + y^{2} - 8 x - 4 y + 4 = 0

What is (x-1)^2+y^2=5 ?
The solution to (x-1)^2+y^2=5 is Circle with (a,b)=(1,0),r=sqrt(5)