What is x^2+8x+y^2+6y=0 ?

The solution to x^2+8x+y^2+6y=0 is Circle with (a,b)=(-4,-3),r=5

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x^2+8x+y^2+6y=0

x^{2} + 8 x + y^{2} + 6 y = 0

(a, b) = (- 4, - 3), r = 5

Solution steps

x^{2} + 8 x + y^{2} + 6 y = 0

Rewrite

x^{2} + 8 x + y^{2} + 6 y = 0

in the form of the standard circle equation

(x - (- 4))^{2} + (y - (- 3))^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 4, - 3), r = 5

x^{2} + y^{2} - 4 x - 3 y + 6 = 0

(X - 2)^{2} + (Y + 4)^{2} = 4

x^{2} + y^{2} + 2 x - 10 y + 22 = 0

(x + 2)^{2} + (y + 3)^{2} = 5

(x + 2)^{2} + (y + 3)^{2} = 4

What is x^2+8x+y^2+6y=0 ?
The solution to x^2+8x+y^2+6y=0 is Circle with (a,b)=(-4,-3),r=5