What is (X-2)^2+(Y+4)^2=4 ?

The solution to (X-2)^2+(Y+4)^2=4 is Circle with (a,b)=(2,-4),r=2

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(X-2)^2+(Y+4)^2=4

(X - 2)^{2} + (Y + 4)^{2} = 4

(a, b) = (2, - 4), r = 2

Solution steps

(X - 2)^{2} + (Y + 4)^{2} = 4

Rewrite

(X - 2)^{2} + (Y + 4)^{2} = 4

in the form of the standard circle equation

(X - 2)^{2} + (Y - (- 4))^{2} = 2^{2}

Therefore the circle properties are:

(a, b) = (2, - 4), r = 2

x^{2} + y^{2} + 2 x - 10 y + 22 = 0

(x + 2)^{2} + (y + 3)^{2} = 5

(x + 2)^{2} + (y + 3)^{2} = 4

(x - 5)^{2} + (y + 6)^{2} = 25

x^{2} + y^{2} + 6 x + 2 y - 26 = 0

What is (X-2)^2+(Y+4)^2=4 ?
The solution to (X-2)^2+(Y+4)^2=4 is Circle with (a,b)=(2,-4),r=2