What is (x-1)^2+(y-4)^2=9 ?

The solution to (x-1)^2+(y-4)^2=9 is Circle with (a,b)=(1,4),r=3

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(x-1)^2+(y-4)^2=9

(x - 1)^{2} + (y - 4)^{2} = 9

(a, b) = (1, 4), r = 3

Solution steps

(x - 1)^{2} + (y - 4)^{2} = 9

Rewrite

(x - 1)^{2} + (y - 4)^{2} = 9

in the form of the standard circle equation

(x - 1)^{2} + (y - 4)^{2} = 3^{2}

Therefore the circle properties are:

(a, b) = (1, 4), r = 3

\frac{x ^{2}}{5} + \frac{y ^{2}}{5} = 53

x^{2} + y^{2} + 4 x + 8 y + 11 = 0

x^{2} + y^{2} + 4 x - 12 y = 0

x^{2} - 14 x + y^{2} + 8 y - 40 = 0

x^{2} + y^{2} - 6 x - 10 y - 15 = 0

What is (x-1)^2+(y-4)^2=9 ?
The solution to (x-1)^2+(y-4)^2=9 is Circle with (a,b)=(1,4),r=3