What is (x^2)/5+(y^2)/5 =53 ?

The solution to (x^2)/5+(y^2)/5 =53 is Circle with (a,b)=(0,0),r=sqrt(265)

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(x^2)/5+(y^2)/5 =53

\frac{x ^{2}}{5} + \frac{y ^{2}}{5} = 53

(a, b) = (0, 0), r = 265

Solution steps

\frac{x ^{2}}{5} + \frac{y ^{2}}{5} = 53

Rewrite

\frac{x ^{2}}{5} + \frac{y ^{2}}{5} = 53

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = (265)^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 265

x^{2} + y^{2} + 4 x + 8 y + 11 = 0

x^{2} + y^{2} + 4 x - 12 y = 0

x^{2} - 14 x + y^{2} + 8 y - 40 = 0

x^{2} + y^{2} - 6 x - 10 y - 15 = 0

x^{2} + y^{2} + 6 x - 12 y + 20 = 0

What is (x^2)/5+(y^2)/5 =53 ?
The solution to (x^2)/5+(y^2)/5 =53 is Circle with (a,b)=(0,0),r=sqrt(265)