What is x^2+y^2+6x-12y+20=0 ?

The solution to x^2+y^2+6x-12y+20=0 is Circle with (a,b)=(-3,6),r=5

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x^2+y^2+6x-12y+20=0

x^{2} + y^{2} + 6 x - 12 y + 20 = 0

(a, b) = (- 3, 6), r = 5

Solution steps

x^{2} + y^{2} + 6 x - 12 y + 20 = 0

Rewrite

x^{2} + y^{2} + 6 x - 12 y + 20 = 0

in the form of the standard circle equation

(x - (- 3))^{2} + (y - 6)^{2} = 5^{2}

Therefore the circle properties are:

(a, b) = (- 3, 6), r = 5

x^{2} + y^{2} + 6 x - 8 y + 9 = 0

x^{2} + y^{2} - 5 x = 0

2 x^{2} + 2 y^{2} - 2 x - 6 y - 13 = 0

(x^{2} + 4 x + 4) + (y^{2} - 8 y + 16) = - 9 + 4 + 16

(x - 20)^{2} + (y - 0.05)^{2} = 81

What is x^2+y^2+6x-12y+20=0 ?
The solution to x^2+y^2+6x-12y+20=0 is Circle with (a,b)=(-3,6),r=5