What is x^2+10x+y^2-16-11=0 ?

The solution to x^2+10x+y^2-16-11=0 is Circle with (a,b)=(-5,0),r=2sqrt(13)

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x^2+10x+y^2-16-11=0

x^{2} + 10 x + y^{2} - 16 - 11 = 0

(a, b) = (- 5, 0), r = 213

Solution steps

x^{2} + 10 x + y^{2} - 16 - 11 = 0

Rewrite

x^{2} + 10 x + y^{2} - 16 - 11 = 0

in the form of the standard circle equation

(x - (- 5))^{2} + (y - 0)^{2} = (213)^{2}

Therefore the circle properties are:

(a, b) = (- 5, 0), r = 213

x^{2} + y^{2} + 10 x - 8 y = - 32

x^{2} - 2 x + y^{2} + 4 y - 20 = 0

(x + 1)^{2} + (y - 1)^{2} = 5

4 x^{2} + 16 x + 15 + 4 y^{2} + 6 y = 0

x^{2} + y^{2} - 2 y - 8 x - 19 = 0

What is x^2+10x+y^2-16-11=0 ?
The solution to x^2+10x+y^2-16-11=0 is Circle with (a,b)=(-5,0),r=2sqrt(13)