What is (x+1)^2+(y-1)^2=5 ?

The solution to (x+1)^2+(y-1)^2=5 is Circle with (a,b)=(-1,1),r=sqrt(5)

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(x+1)^2+(y-1)^2=5

(x + 1)^{2} + (y - 1)^{2} = 5

(a, b) = (- 1, 1), r = 5

Solution steps

(x + 1)^{2} + (y - 1)^{2} = 5

Rewrite

(x + 1)^{2} + (y - 1)^{2} = 5

in the form of the standard circle equation

(x - (- 1))^{2} + (y - 1)^{2} = (5)^{2}

Therefore the circle properties are:

(a, b) = (- 1, 1), r = 5

4 x^{2} + 16 x + 15 + 4 y^{2} + 6 y = 0

x^{2} + y^{2} - 2 y - 8 x - 19 = 0

x^{2} - 4 x + y^{2} = 3 + 6 y

(x^{2} - 4 x) + (y^{2} - 6 y) = - 9

2 x^{2} + 2 y^{2} - 2 x + 2 y - 1 = 0

What is (x+1)^2+(y-1)^2=5 ?
The solution to (x+1)^2+(y-1)^2=5 is Circle with (a,b)=(-1,1),r=sqrt(5)