What is (x-3)^2+(y-2)^2=36 ?

The solution to (x-3)^2+(y-2)^2=36 is Circle with (a,b)=(3,2),r=6

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(x-3)^2+(y-2)^2=36

(x - 3)^{2} + (y - 2)^{2} = 36

(a, b) = (3, 2), r = 6

Solution steps

(x - 3)^{2} + (y - 2)^{2} = 36

Rewrite

(x - 3)^{2} + (y - 2)^{2} = 36

in the form of the standard circle equation

(x - 3)^{2} + (y - 2)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (3, 2), r = 6

x^{2} + y^{2} - 4 x - 2 y - 3 = 0

x^{2} + y^{2} - 3 = 0

x^{2} + y^{2} - \frac{1}{4} x + \frac{1}{4} y = \frac{7}{32}

(x - 3)^{2} + y^{2} = 1

3 x^{2} + 3 y^{2} - 4 x + y - 12 = 0

What is (x-3)^2+(y-2)^2=36 ?
The solution to (x-3)^2+(y-2)^2=36 is Circle with (a,b)=(3,2),r=6