What is x^2+y^2-1/4 x+1/4 y= 7/32 ?

The solution to x^2+y^2-1/4 x+1/4 y= 7/32 is Circle with (a,b)=(1/8 ,-1/8),r= 1/2

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x^2+y^2-1/4 x+1/4 y= 7/32

x^{2} + y^{2} - \frac{1}{4} x + \frac{1}{4} y = \frac{7}{32}

(a, b) = (\frac{1}{8}, - \frac{1}{8}), r = \frac{1}{2}

Solution steps

x^{2} + y^{2} - \frac{1}{4} x + \frac{1}{4} y = \frac{7}{32}

Rewrite

x^{2} + y^{2} - \frac{1}{4} x + \frac{1}{4} y = \frac{7}{32}

in the form of the standard circle equation

(x - \frac{1}{8})^{2} + (y - (- \frac{1}{8}))^{2} = (\frac{1}{2})^{2}

Therefore the circle properties are:

(a, b) = (\frac{1}{8}, - \frac{1}{8}), r = \frac{1}{2}

(x - 3)^{2} + y^{2} = 1

3 x^{2} + 3 y^{2} - 4 x + y - 12 = 0

x^{2} + y^{2} \leq 10

x^{2} + y^{2} \leq 36

4 x^{2} - 4 x + 4 y^{2} - 35 = 0

What is x^2+y^2-1/4 x+1/4 y= 7/32 ?
The solution to x^2+y^2-1/4 x+1/4 y= 7/32 is Circle with (a,b)=(1/8 ,-1/8),r= 1/2