What is x^2+y^2<= 36 ?

The solution to x^2+y^2<= 36 is Circle with (a,b)=(0,0),r=6

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x^2+y^2<= 36

x^{2} + y^{2} \leq 36

(a, b) = (0, 0), r = 6

Solution steps

x^{2} + y^{2} \leq 36

Rewrite

x^{2} + y^{2} \leq 36

in the form of the standard circle equation

(x - 0)^{2} + (y - 0)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (0, 0), r = 6

4 x^{2} - 4 x + 4 y^{2} - 35 = 0

y^{2} = 10 - z^{2}

3 x^{2} + 3 y^{2} - 6 x + 5 y = 0

x^{2} - 8 x + y^{2} - 20 = 0

16 x^{2} + 16 y^{2} + 16 x + 40 y - 7 = 0

What is x^2+y^2<= 36 ?
The solution to x^2+y^2<= 36 is Circle with (a,b)=(0,0),r=6