What is x^2-8x+y^2-20=0 ?

The solution to x^2-8x+y^2-20=0 is Circle with (a,b)=(4,0),r=6

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x^2-8x+y^2-20=0

x^{2} - 8 x + y^{2} - 20 = 0

(a, b) = (4, 0), r = 6

Solution steps

x^{2} - 8 x + y^{2} - 20 = 0

Rewrite

x^{2} - 8 x + y^{2} - 20 = 0

in the form of the standard circle equation

(x - 4)^{2} + (y - 0)^{2} = 6^{2}

Therefore the circle properties are:

(a, b) = (4, 0), r = 6

16 x^{2} + 16 y^{2} + 16 x + 40 y - 7 = 0

(x - 1)^{2} + (y - 2)^{2} = 3

x^{2} + (y - 5)^{2} = 9

x^{2} + 8 y = - y^{2} + 6 x

x^{2} + y^{2} + 4 x - 10 y = 4

What is x^2-8x+y^2-20=0 ?
The solution to x^2-8x+y^2-20=0 is Circle with (a,b)=(4,0),r=6